mirror of
https://github.com/jazzband/django-admin-sortable.git
synced 2026-03-27 19:20:31 +00:00
014f6d1660
Updated version to 1.4.5. Updated README with explanation of requirements for overriding queryset() on inline models. Added extra models to sample project to demonstrate sortable models with custom querysets. Improved JavaScript of sortables to be more efficient with better comparison checking. Fixed highlighting of stacked inlines on sort finish.
79 lines
2.4 KiB
Python
79 lines
2.4 KiB
Python
from django.contrib.contenttypes.models import ContentType
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from django.db import models
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from adminsortable.fields import SortableForeignKey
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class MultipleSortableForeignKeyException(Exception):
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def __init__(self, value):
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self.value = value
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def __str__(self):
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return repr(self.value)
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class Sortable(models.Model):
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"""
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Unfortunately, Django doesn't support using more than one AutoField
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in a model or this class could be simplified.
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`is_sortable` determines whether or not the Model is sortable by
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determining if the last value of `order` is greater than the default
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of 1, which should be present if there is only one object.
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`model_type_id` returns the ContentType.id for the Model that
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inherits Sortable
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`save` the override of save increments the last/highest value of
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order by 1
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"""
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order = models.PositiveIntegerField(editable=False, default=1,
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db_index=True)
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is_sortable = False
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# legacy support
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sortable_by = None
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class Meta:
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abstract = True
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ordering = ['order']
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# @classmethod
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# def determine_if_sortable(cls):
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# try:
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# max_order = cls.objects.aggregate(
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# models.Max('order'))['order__max']
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# except (TypeError, IndexError):
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# max_order = 0
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# if max_order > 1:
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# cls.is_sortable = True
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# else:
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# cls.is_sortable = False
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@classmethod
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def model_type_id(cls):
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return ContentType.objects.get_for_model(cls).id
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def __init__(self, *args, **kwargs):
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super(Sortable, self).__init__(*args, **kwargs)
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# Validate that model only contains at most one SortableForeignKey
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sortable_foreign_keys = []
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for field in self._meta.fields:
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if isinstance(field, SortableForeignKey):
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sortable_foreign_keys.append(field)
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if len(sortable_foreign_keys) > 1:
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raise MultipleSortableForeignKeyException(
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u'%s may only have one SortableForeignKey' % self)
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def save(self, *args, **kwargs):
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if not self.id:
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try:
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self.order = self.__class__.objects.aggregate(
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models.Max('order'))['order__max'] + 1
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except (TypeError, IndexError):
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pass
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super(Sortable, self).save(*args, **kwargs)
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